Quote:
Originally Posted by MITE46
Someone double check my math...
32kWh for full charge
230W for high end solar panel 3' by 5'
19% efficiency for these PV cells
8 hours of sunlight/day
230W per panel * 19% * 8 hours = 350Wh per panel
32kWh / 350Wh = 92 panels (1380 sq feet of southern facing roof,
Unless you have a solar farm, I think it's pretty hard to get 92 panels at home? Am I missing something here?
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Here is how to calculate the power output:
1. DC Rating of the Panels x Number of Panels = Capacity of the system
2. Use NREL PVWatts to Determine the output (kWh/year) (
http://mapserve3.nrel.gov/PVWatts_Viewer/index.html) with inputs:
- Address
- Capacity
- Tilt
- Azimuth (180 = due south)
- DC to AC Derate Factor (use 0.8)
Keep in mind that panel efficiency deals with the number of watts per sq.ft. that the panels can produce and that weather characteristics along with the quality of the installation (wiring, inverter efficiency, etc.) determine the amount of kWhs that can be produced per watt of system capacity.