08-03-2011, 03:37 PM | #45 |
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Awesome.
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08-03-2011, 04:19 PM | #48 |
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To those who asked about the wheels:
More pics of his 1M can be found at: http://www.milorifilms.com/
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08-03-2011, 04:27 PM | #50 |
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We are set to make one tomorrow when Lare comes back in town.
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08-03-2011, 04:38 PM | #51 |
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very respectable #'s
eisenmann (1st in na)
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08-03-2011, 10:59 PM | #57 |
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sweet!
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08-04-2011, 04:00 AM | #58 | ||||||
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It should be the same, but you will benefit from higher octane levels.
Agreed! That would be Eisenmann Race full exhaust, downpipes back! What you mean what happend to the tires? Thanks! Quote:
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08-04-2011, 07:01 AM | #59 |
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sound clip?
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08-04-2011, 08:59 AM | #60 | |
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If you had after tax earnings of $85 and your tax rate was 15%, would you multiply 85*1.15 to get your before tax earnings. No. You would take 85/(1-.15). Granted, with a dyno the drivetrain loss is unknown, but the appropriate way to back into crank is to divide by (1 - drivetrain loss %). |
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08-04-2011, 09:09 AM | #61 | |
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Quote:
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08-04-2011, 09:26 AM | #62 |
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Here's the thing, and why I use my equation. If a car rated SAE at 400hp comes in and makes 340rwhp then you are correct, and using the 340/(1-.15) method works great. However the average hp for a car rated at 400 is usually around 348 or so (keep in mind, I'm just using this as an example). Now if we use your method then the car is making 409hp at the flywheel, which may or my not be wrong, who knows. Now, about 99% of my clients have the 15% number drilled into their head. The actual drive train loss might actually be around 13%. In this case, your formula works. The problem is that the clients want to use the 15% number for whatever reason, and from a business standpoint it makes more sense for me to use my method. If I use X/(1-.15) then the tag starts floating around the the dyno is "generous" and bloats numbers. If I use the 15% loss variable that the client wants to use then I have to do it my way...from a business standpoint, so that is the real reason behind my method. Does that make sense?
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08-04-2011, 09:52 AM | #64 |
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08-04-2011, 09:55 AM | #65 |
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Like I said, If we knew the exact magical number then I agree, at is the method you should use. I have just never been able to get that number to back up anything that I see scientifically on the dyno when using the "magical" 15% that everyone is comfortable with.
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08-04-2011, 10:00 AM | #66 |
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The thing is, I hate even guess what FWhp is on a car. It doesn't matter what number or method you use. I would wager my car that there is a 100% chance that if you yanked the motor and placed it on a engine dyno the numbers would not match up with what you were calculating them to be.
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