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10152014, 10:51 PM  #2 
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Drives: 1M VO  #161 US
Join Date: Sep 2014
Location: Portland  the Real one  in Oregon

Well, the 1M weighs about 3300lbs, and has approximately 330HP, i.e. around 10lb/hp, thus...
The answer is left for the student... 
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10162014, 07:40 AM  #3  
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Drives: L'Orange
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10162014, 09:20 AM  #4 
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Although I don't have the answer, I believe that the OP is asking a different question than has been answered.
Since lighter is faster, how many pounds of weight reduction is comparable to a hp of increased power? Probably could google it... Neil 
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10162014, 09:50 AM  #5 
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Best way to look at it is to just take your rated Rate/HP.
For example, a 128i with full fluids weighs in at 3200 lbs at rated 230 HP. That'll give me a 13.91 lb/hp ratio. I'm currently weighed in at 2981 lbs in race trim at 250.7 bhp (assuming 15% drivetrain loss from my dyno) That'll put me at now 11.89 lb/hp So I effectively increased my lb/hp by 14.5% I know this doesn't answer the question, but it is the easiest way to look at things 
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10162014, 10:18 AM  #6 
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OK, I googled it. This article is pretty good.
http://www.tuneruniversity.com/blog/...weightratio/ Neil 
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10162014, 11:26 AM  #7  
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Initial Starting Weight (lbs) / Improved Weight to Power Ratio from mods (lbs/Hp) = New HP equivalent. 3300 lbs / 335 hp = 9.85 lbs per HP. Car is lightened to 3100 lbs with 335 hp, ratio improves to 9.25 lbs per hp. So 3300 / 9.25 = 356.75 hp equivalent at 3100 lbs. 

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10172014, 12:39 AM  #8  
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10172014, 12:40 AM  #9  
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