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      06-02-2014, 12:31 AM   #1
BadOneThreeFive
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Need someone's math skills

I'm in need of someone's math skills because mine are horrible.

Ok, so I purchased one gallon of boost juice which is a 50/50 mix of methanol and distilled water. I want to achieve an 75/25 mix of meth/water.

How many 12oz bottles of HEET (100% meth) do I need to add to the one gallon to reach the 75/25?

Thanks.
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      06-02-2014, 01:11 AM   #2
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      06-02-2014, 06:15 AM   #3
SteveAZ
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If you take 1 gallon of pure meth (10.6 bottles of heat) and add it to 1 gallon of 50% meth....you'll end up with 2 gallons of 75% meth
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      06-02-2014, 10:38 AM   #4
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Try the excel sheet I found online. From what I can tell you will need 15 if calculating by weight and 9 by volume to get a 75/25 mixture.
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File Type: zip MethanolMixingToolkit.zip (19.9 KB, 90 views)
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      06-02-2014, 12:14 PM   #5
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128oz to 1 gallon, 12oz per bottle, so you need 10.67 (10 2/3) bottles of 100% meth to achieve 75% mix, total final volume will obviously be 2 gallons.


Edit: SteveAZ beat me to it.
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